ln(e^2+1)+ln(e+1)=1

Solution for ln(e^2+1)+ln(e+1)=1 equation:

Simplifying
ln(e2 + 1) + ln(e + 1) = 1

Reorder the terms:
ln(1 + e2) + ln(e + 1) = 1
(1 * ln + e2 * ln) + ln(e + 1) = 1

Reorder the terms:
(e2ln + 1ln) + ln(e + 1) = 1
(e2ln + 1ln) + ln(e + 1) = 1

Reorder the terms:
e2ln + 1ln + ln(1 + e) = 1
e2ln + 1ln + (1 * ln + e * ln) = 1

Reorder the terms:
e2ln + 1ln + (eln + 1ln) = 1
e2ln + 1ln + (eln + 1ln) = 1

Reorder the terms:
eln + e2ln + 1ln + 1ln = 1

Combine like terms: 1ln + 1ln = 2ln
eln + e2ln + 2ln = 1

Solving
eln + e2ln + 2ln = 1

Solving for variable 'e'.

Reorder the terms:
-1 + eln + e2ln + 2ln = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + eln + e2ln + 2ln = 0

The solution to this equation could not be determined.